The proton \(N M R\) chemical shifts of the hydrogens in pyridine are shown. These are typical aromatic chemical shifts, except that the ortho protons (on the carbons bonded to nitrogen) are deshielded to \(\delta 8.60\). A suitable oxidizing agent (such as a peroxyacid) can add an oxygen atom to pyridine to give pyridine \(N-\text { oxide }\). The effect of this added oxygen atom is to shift the ortho protons upfield from \(\delta 8.60 \text { to } \delta 8.19\) The meta protons are shifted downfield from \(\delta 7.25\) to \(\delta 7.40\). The para protons are shifted upfield, from \(\delta 7.64 \text { to } \delta 7.32\) Explain this curious effect, shifting some protons upfield and others downfield. Equation Transcription: Text Transcription: N M R \delta 8.60 N-\text { oxide } \delta 8.60 \text { to } \delta 8.19 \delta 7.25 \delta 7.40 \delta 7.64 \text { to } \delta 7.32
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Textbook Solutions for Organic Chemistry
Question
The following molecules and ions are grouped by similar structures. Classify each as aromatic, antiaromatic, or nonaromatic. For the aromatic and antiaromatic species, give the number of pi electrons in the ring.
Solution
Step 1 of 11
The cyclic compounds are classified under aromatic, anti-aromatic, and non-aromatic classes based on some structural features. “Huckel’s rule is used to predict aromatic character” and according to this rule following features are necessary for a compound to be aromatic.
Cyclic structure
Conjugation
Planarity
\(\left(4n+2\right)\pi\ e^{-}\)
Here, “n denotes a positive integer and it can be a zero.”
If a compound has “cyclic structure, conjugation, and planarity but have \(\left(4n\right)\pi\ e^{-}\)” is considered as anti-aromatic.
The compound which lacks “cyclic structure, conjugation, planarity and have \(\left(4n\right)\pi\ e^{-}\) or\(\left(4n+2\right)\pi\ e^{-}\)” any feature/ features are considered as non-aromatic.
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