If Z is a standard normal random variable, find the value

Chapter 4, Problem 59E

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QUESTION:

If Z is a standard normal random variable, find the value z0 such that

a \(P\left(Z>z_{0}\right)=.5\).

b \(P\left(Z<z_{0}\right)=.8643\).

c \(P\left(-z_{0}<Z<z_{0}\right)=.90\).

d \(P\left(-z_{0}<Z<z_{0}\right)=.99\)

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QUESTION:

If Z is a standard normal random variable, find the value z0 such that

a \(P\left(Z>z_{0}\right)=.5\).

b \(P\left(Z<z_{0}\right)=.8643\).

c \(P\left(-z_{0}<Z<z_{0}\right)=.90\).

d \(P\left(-z_{0}<Z<z_{0}\right)=.99\)

ANSWER:

Step 1 of 4

(a)

If Z is a standard normal random variable, find the value \(z_{0}\) such that

\(P\left(Z>z_{0}\right)=0.5\)

In Table 4, Appendix 3, we have given the tabulated areas (probability) are to the right of points z, where z is the distance from the mean, measured in standard deviations.

\(P\left(Z>z_{0}\right)=\text { area to the right points of } z_{0}=0.5\)

Hence we will check the value of \(z_{0}\) from Table 4, Appendix 3, for which the area or \(P\left(Z>z_{0}\right)\)

Will be 0.5.

From the normal distribution table, we can see that the value of \(z_{0}\) is 0.

Hence the value of \(z_{0}\) is 0.

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