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Comparing Example 12.1 (Section 12.1) and Example 12.2

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 3DQ Chapter 12

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 3DQ

Comparing Example 12.1 (Section 12.1) and Example 12.2 (Section 12.2), it seems that 700 N of air is exerting a downward force of 2.0 × 106 N on the floor. How is this possible?

Step-by-Step Solution:

Solution 3DQ Step 1 of 2: Inside the living room we have air, as air is in gaseous state; the atoms are molecules in gaseous are free to move in random direction. So the air molecules inside the room, tends to move in random direction with some greater speeds. Some of the air molecules near the walls and floor hits the walls and floor during their random motion. As this air molecules repeatedly hits or collides with the floor, they create some pressure on the pressure. Pressure is defined as the force per unit area, F P = A Therefore, the pressure created by the air molecules will exert some force on the floor, which depends on the mass as well as the density of air.

Step 2 of 2

Chapter 12, Problem 3DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Comparing Example 12.1 (Section 12.1) and Example 12.2

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