A 0.180-kg cube of ice (frozen water) is floating in | StudySoup

Textbook Solutions for University Physics

Chapter 12 Problem 57P

Question

A 0.180-kg cube of ice (frozen water) is floating in glycerine. The gylcerine is in a tall cylinder that has inside radius 3.50 cm. The level of the glycerine is well below the top of the cylinder. If the ice completely melts, by what distance does the height of liquid in the cylinder change? Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerine before the ice melted?

Solution

Solution 57P Introduction We have to calculate the change in the height of the liquid in the tube after ice melts. Step 1 The mass of the ice is m = 0.180 kg = 180 g . Hence the mass of the displaced glycerine is m = 180 g 3 The density of glycerine is g= 1.26 g/cm Hence the volume of the displaced glycerine is m 180 g 3 V =g g= 1.26 g/cm 142.9 cm

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

A 0.180-kg cube of ice (frozen water) is floating in

Chapter 12 textbook questions

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