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Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 41e
Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 41e

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# A sealed tank containing seawater to a height of 11.0 m

ISBN: 9780321675460 31

## Solution for problem 41E Chapter 12

University Physics | 13th Edition

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Problem 41E

A sealed tank containing seawater to a height of 11.0 m also contains air above the water at a gauge pressure of 3.00 atm. Water flows out from the bottom through a small hole. How fast is this water moving?

Step-by-Step Solution:
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Solution 41E The efflux speed of the water from the bottom of the tank is given by, P 0P atm v = 2( ) + 2gh…..(1) Where, (P 0 P) is the gauge pressure, is seawater density, h is the height of water in the tank. 5 Given, gauge pressure P 0 P = 3.00 atm = 3.00 × 1.01 × 10 Pa Height h = 11.0 m Seawater density = 1025 kg/m 3 Acceleration due to gravity g = 9.80 m/s2 Substituting these value in equation (1), we get v = 2 × 3.00×1.01×10+ 2 × 9.80 × 11.0 1025 v = 805 m/s v = 28.4 m/s The water is moving at a speed of 28.4 m/s.

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##### ISBN: 9780321675460

The answer to “A sealed tank containing seawater to a height of 11.0 m also contains air above the water at a gauge pressure of 3.00 atm. Water flows out from the bottom through a small hole. How fast is this water moving?” is broken down into a number of easy to follow steps, and 40 words. Since the solution to 41E from 12 chapter was answered, more than 887 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 41E from chapter: 12 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: Water, height, atm, bottom, containing. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

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