An automobile engine slows down from 4500 rpm to 1200 rpm in 2.5 s. Calculate (a) its angular acceleration, assumed constant, and (b) the total number of revolutions the engine makes in this time.
Solution: The uniform material in the above figure we need to find what is the greatest that x can be without the object tipping over Step 1 Where the centre of gravity depends on the distances x , x , of each particle o f mass m , 1 2 1 m ,2from the origin. x m + x m + x m + .. x = 1 1 2 2 3 3 cg m +1m + 2 + .3 xcgis the centre of gravity, The density of the substance or material is defined as the mass (m) and volume (V). m = V Therefore, the mass of the substance can be written as, m = V Step 2 The uniform of the material in the object as shown in the figure, C.g = centre of gravity
Textbook: Physics: Principles with Applications
Author: Douglas C. Giancoli
Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. The answer to “An automobile engine slows down from 4500 rpm to 1200 rpm in 2.5 s. Calculate (a) its angular acceleration, assumed constant, and (b) the total number of revolutions the engine makes in this time.” is broken down into a number of easy to follow steps, and 34 words. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. Since the solution to 16P from 8 chapter was answered, more than 378 students have viewed the full step-by-step answer. This full solution covers the following key subjects: engine, rpm, acceleration, angular, assumed. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The full step-by-step solution to problem: 16P from chapter: 8 was answered by , our top Physics solution expert on 03/03/17, 03:53PM.