Professional Application Ernest Rutherford (the first New | StudySoup

Textbook Solutions for Physics: Principles with Applications

Chapter 8 Problem 49PE

Question

Professional Application Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (4He) from gold-197 nuclei (197 Au). The energy of the incoming helium nucleus was 8.00×10?13 J , and the masses of the helium and gold nuclei were 6.68×10?27 kg and 3.29×10?25 kg , respectively (note that their mass ratio is 4 to 197). (a) If a helium nucleus scatters to an angle of 120º during an elastic collision with a gold nucleus, calculate the helium nucleus’s final speed and the final velocity (magnitude and direction) of the gold nucleus. (b) What is the final kinetic energy of the helium nucleus?

Solution

Step-by-step solution In this problem we have to find the final speed and the final velocity of the gold nucleus and expression to find the final kinetic energy of helium Step 1 of 9 (a) The expression to find the kinetic energy is, Rearrange the expression for velocity. Here, is kinetic energy, is mass and is initial velocity of Helium.

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full solution

Title Physics: Principles with Applications 6 
Author Douglas C. Giancoli
ISBN 9780130606204

Professional Application Ernest Rutherford (the first New

Chapter 8 textbook questions

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