Because acid–base and precipitation reactions discussed in | StudySoup

Textbook Solutions for Chemistry

Chapter 4 Problem 174P

Question

Because acid–base and precipitation reactions discussed in this chapter all involve ionic species, their progress can be monitored by measuring the electrical conductance of the solution. Match the following reactions with the diagrams shown here. The electrical conductance is shown in arbitrary units.

(1)        A 1.0 M KOH solution is added to 1.0 L of 1.0 M \(\mathrm{CH}_{3} \mathrm{COOH}\).

(2)        A 1.0 M NaOH solution is added to 1.0 L of 1.0 M HCl.

(3) A 1.0 M \(\mathrm{BaCl}_{2}\) solution is added to 1.0 L of 1.0 M \(\mathrm{K}_{2} \mathrm{SO}_{4}\).

(4) A 1.0 M NaCl solution is added to 1.0 L of 1.0 M \(\mathrm{AgNO}_{3}\).

(5) A 1.0 M \(\mathrm{CH}_{3} \mathrm{COOH}\) solution is added to 1.0 Lof 1.0 M \(\mathrm{NH}_{3}\).

 

Solution

Step 1 of 6

Here, we are going to match the given reaction with electrical conductance in the diagram.

 

If the molecule is dissociated into the solution having ions with charge +1 and -1 then the electrical conductance will be twice to its molarity.

Similarly, if the  molecule is dissociated into the solution having ions with charge +2 and -2 then the electrical conductance will be four times to its molarity.

 

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full solution

Title Chemistry 11 
Author Raymond Chang
ISBN 9780073402680

Because acid–base and precipitation reactions discussed in

Chapter 4 textbook questions

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