Solved: A 5.012-g sample of an iron chloride hydrate was | StudySoup

Textbook Solutions for Chemistry

Chapter 4 Problem 128P

Question

A 5.012-g sample of an iron chloride hydrate was dried in an oven. The mass of the anhydrous compound was 3.195 g. The compound was then dissolved in water and reacted with an excess of \(\mathrm{AgNO}_{3}\). The AgCl precipitate formed weighed 7.225 g. What is the formula of the original compound?

Solution

Step 1 of 4

Here, we are find out the formulae of the original compound from the given data.

To calculate the moles of hydrate by using the difference in mass between the anhydrous iron chloride and iron chloride.

Iron chloride weight = 5.012g

Anhydrous iron chloride weight = 3.195g

5.012 g - 3.195 g = 1.817 g   ×  = 0.1008 mol of .

Moles of Hydrates is  0.1008 mol.

______________________________________________________________________________

Subscribe to view the
full solution

Title Chemistry 11 
Author Raymond Chang
ISBN 9780073402680

Solved: A 5.012-g sample of an iron chloride hydrate was

Chapter 4 textbook questions

×

Login

Organize all study tools for free

Or continue with
×

Register

Sign up for access to all content on our site!

Or continue with

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back