How many milliliters of a 0.206 M HI solution are needed | StudySoup

Textbook Solutions for Chemistry

Chapter 4 Problem 13PE

Question

How many milliliters of a 0.206 M HI solution are needed to reduce 22.5 mL of a 0.374 M \(\mathrm{KMnO}_{4}\) solution according to the following equation:

\(10 \mathrm{HI}+2 \mathrm{KMnO}_{4}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow 5 \mathrm{I}_{2}+2 \mathrm{MnSO}_{4}+\mathrm{K}_{2} \mathrm{SO}_{4}+8 \mathrm{H}_{2} \mathrm{O}\)

Solution

Step 1 of 3

Here, we are going to calculate the volume of HI required to reduce 22.5 mL of a 0.374 M  solution.

 

The balanced equation is :

The volume of  = 22.5 mL

The strength of  = 0.374 M

 

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full solution

Title Chemistry 11 
Author Raymond Chang
ISBN 9780073402680

How many milliliters of a 0.206 M HI solution are needed

Chapter 4 textbook questions

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