Solved: Give oxidation numbers for the underlined atoms in | StudySoup

Textbook Solutions for Chemistry

Chapter 4 Problem 49P

Question

Give oxidation numbers for the underlined atoms in the following molecules and ions:

(a) \(\underline{C s}_{2} \mathrm{O}\)

(b) \(\mathrm{Ca \underline I}_{2}\)

(c) \(\underline{A l}_{2} \mathrm{O}_{3}\)

(d) \(\mathrm{H}_{3} \underline{A s O}_{3}\)

(e) \(\underline{\mathrm{Ti}} \mathrm{O}_{2}\)

(f) \(\underline {Mo} {\mathrm {O}_{4}^{2-}}\)

(g) \(\underline{P t} \mathrm{Cl}_{4}^{2-}\)

(h) \(\underline{P t} \mathrm{Cl}_{6}^{2-}\)

(i) \(\underline{\operatorname{Sn}} F_{2}\)

(j) \(\underline{C l} F_{3}\)

(k) \(\underline{S b} F_{6}^{-}\)

Solution

Step 1 of 11

(a) \(\underline{\mathrm{Cs}}_{2} \mathrm{O}\)

Here we have to calculate the oxidation number of Cs, let us consider its oxidation number is x.

It is known that the oxidation state of  O is -2

The oxidation state of Cs in \(\mathrm{Cs}_{2} \mathrm{O}\) can be calculated as,

Number of atom of Cs (oxidation state of Cs) + Number of atom of O (oxidation state of O) = charge on the compound

\(\begin{array}{c} 2 \mathrm{x}+(-2)=0 \\ \Rightarrow 2 \mathrm{x}-2=0 \\ \mathrm{x}=+1 \end{array}\)

Hence the oxidation state Cs is +1.

 

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full solution

Title Chemistry 11 
Author Raymond Chang
ISBN 9780073402680

Solved: Give oxidation numbers for the underlined atoms in

Chapter 4 textbook questions

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