Solution Found!
A gas initially at 4.0 L, 1.2 atm, and 66°C undergoes a
Chapter 5, Problem 7PE(choose chapter or problem)
A gas initially at \(4.0 \mathrm{~L}, 1.2\) atm, and \(66^{\circ} \mathrm{C}\) undergoes a change so that its final volume and temperature are \(1.7 \mathrm{~L}\) and \(42^{\circ} \mathrm{C}\). What is its final pressure? Assume the number of moles remains unchanged.
Questions & Answers
QUESTION:
A gas initially at \(4.0 \mathrm{~L}, 1.2\) atm, and \(66^{\circ} \mathrm{C}\) undergoes a change so that its final volume and temperature are \(1.7 \mathrm{~L}\) and \(42^{\circ} \mathrm{C}\). What is its final pressure? Assume the number of moles remains unchanged.
ANSWER:Step 1 of 2
Here we have to calculate the final pressure.
In this question it has been given that the number of moles of a gas remains unchanged and the gas has,
The initial volume \(\left(\mathrm{V}_{1}\right)=4.0 \mathrm{~L}\)
Initial pressure \(\left(\mathrm{P}_{1}\right)=1.2 \mathrm{~atm}\)
Initial temperature \(\left(\mathrm{T}_{1}\right)=66^{\circ}=273+66=339 \mathrm{~K}\)
The final volume \(\left(\mathrm{V}_{2}\right)=1.7 \mathrm{~L}\)
Final temperature \(\left(\mathrm{T}_{2}\right)=42^{\circ} \mathrm{C}=273+42=315 \mathrm{~K}\)
Final pressure \(\left(\mathrm{P}_{2}\right)=?\)