A gas initially at 4.0 L, 1.2 atm, and 66°C undergoes a | StudySoup

Textbook Solutions for Chemistry

Chapter 5 Problem 7PE

Question

A gas initially at \(4.0 \mathrm{~L}, 1.2\) atm, and \(66^{\circ} \mathrm{C}\) undergoes a change so that its final volume and temperature are \(1.7 \mathrm{~L}\) and \(42^{\circ} \mathrm{C}\). What is its final pressure? Assume the number of moles remains unchanged.

Solution

Step 1 of 2

Here we have to calculate the final pressure.

In this question it has been given that the number of moles of a gas remains unchanged and the gas has,

The initial volume \(\left(\mathrm{V}_{1}\right)=4.0 \mathrm{~L}\)

Initial pressure \(\left(\mathrm{P}_{1}\right)=1.2 \mathrm{~atm}\)

Initial temperature \(\left(\mathrm{T}_{1}\right)=66^{\circ}=273+66=339 \mathrm{~K}\)

The final volume \(\left(\mathrm{V}_{2}\right)=1.7 \mathrm{~L}\)

Final temperature \(\left(\mathrm{T}_{2}\right)=42^{\circ} \mathrm{C}=273+42=315 \mathrm{~K}\)

Final pressure \(\left(\mathrm{P}_{2}\right)=?\)

 

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full solution

Title Chemistry 11 
Author Raymond Chang
ISBN 9780073402680

A gas initially at 4.0 L, 1.2 atm, and 66°C undergoes a

Chapter 5 textbook questions

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