Suppose that Y is a discrete random variable with mean ? | StudySoup

Textbook Solutions for Mathematical Statistics with Applications

Chapter 3 Problem 30E

Question

Suppose that is a discrete random variable with mean and variance \(\sigma^{2}\) and let \(X=Y+1\).

a Do you expect the mean of to be larger than, smaller than, or equal to \(\mu=E(Y)\)? Why?

b Use Theorems and to express \(E(X)=E(Y+1)\) in terms of \(\mu=E(Y)\). Does this result agree with your answer to part (a)?

c Recalling that the variance is a measure of spread or dispersion, do you expect the variance of to be larger than, smaller than, or equal to \(\sigma^{2}=V(Y)\)? Why?

3. Exercises preceded by an asterisk are optional.

d Use Definition and the result in part (b) to show that

\(V(X)=E\left\{[X-E(X)]^{2}\right\}=E\left[(Y-\mu)^{2}\right]=\sigma^{2}\);

that is, \(X=Y+1\) and have equal variances.

Solution

Solution:

Step 1 of 3:

Given,  let Y is a discrete random variable with mean  and variance ,

X = Y + 1

  1. The claim is to suggest that the mean of the X to be larger than, smaller than, or equal to  = E(Y).

We have , X = Y + 1

Take expectation

E(X) = E(Y + 1)

        = E(Y) + 1

We know that, E(Y) =

Therefore, E(X) =  + 1, which is greater than .

Hence, the mean of the X to be larger than  = E(Y).


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full solution

Title Mathematical Statistics with Applications  7 
Author Dennis Wackerly; William Mendenhall; Richard L. Scheaffer
ISBN 9780495110811

Suppose that Y is a discrete random variable with mean ?

Chapter 3 textbook questions

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