Each of the following compounds exhibits a 1 H NMR spectrum with only one signal. Deduce the structure of each compound: (a) C5H10 (b) C5H8Cl4 (c) C12H18
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Textbook Solutions for Organic Chemistry
Question
Determine the structure of an alcohol with molecular formula C4H10O that exhibits the following signals in its 13C NMR spectra: (a) Broadband decoupled: 69.3 d, 32.1 d, 22.8 d, and 10.0 d (b) DEPT-90: 69.3 d (c) DEPT-135: positive signals at 69.3 d, 22.8 d, and 10.0 d; negative signal at 32.1 d
Solution
Step 1 of 5
This exercise asks us to determine the structure of an unknown alcohol with molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) that exhibits the following signals in its \({ }^{13} \mathrm{C}\) NMR spectra:
a) Broadband decoupled: \(69.3 \boldsymbol{\delta}, 32.1 \boldsymbol{\delta}, 22.8 \boldsymbol{\delta}\), and \(10.0 \boldsymbol{\delta}\).
b) DEPT-90: \(69.3 \delta\)
c) DEPT-135: positive signals at \(69.3 \delta, 22.8 \delta\), and \(10.0 \delta\) with a negative signal at \(32.1 \delta\).
Recall that "broadband-decoupled" refers to a standard \({ }^{13} \mathrm{C}\) NMR spectrum. In a DEPT- 90 spectrum, only carbons with one proton attached \((\mathrm{CH})\) show a signal. In a DEPT-135 spectrum, methyl groups as well as \(\mathrm{CH}\) carbons show a positive signal while a \(\mathrm{CH}_{2}\) group displays a negative signal. A carbon with no attached hydrogens doesn't show any signal in a DEPT-135 spectrum.
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