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Three forces are applied to a wheel of radius 0.350 m, as

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 4E Chapter 10

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 4E

Three forces are applied to a wheel of radius 0.350 m, as shown in ?Fig. E10.4?. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center?

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Solution 4E We have to calculate the net torque on the wheel due to the given forces. Mathematically, Torque = Force X Perpendicular distance between the force and the axis. Let us have a look at the following figure. Force 11.9 N The perpendicular distance of this force from the axis is zero. Therefore, this force can not produce a torque. So, torque produced by 11.9 N force is zero. = 0 1 Force 8.50 N The perpendicular distance of this force from the axis of rotation is 0.350 m. Moreover, this force acts counterclockwise. Hence the torque produced by it will be positive. Torque by the force 8.50 N, 2 = 8.50 N × 0.350 m = 2.97 N.m Force 14.6 N This force has two components that has been shown in the figure above. The 0 0 x-component is 14.6 cos 40 and the y-component is 14.6 sin 40 . The x-component has a perpendicular distance of zero from the axis of rotation. Therefore, the torque produced by it is zero. The y-component has a perpendicular distance of 0.350 m from the axis. But this component will act clockwise and hence the torque produced by it will be negative. Therefore, torque produced by this force, = 14.6 sin 40 N × 0.350 m 3 = 3.28 N.m 3 Therefore, the net torque on the wheel due to all the force is, = +1 + 2 3 = 0 + 2.97 N.m 3.28 N.m = 0.31 N.m The net torque is -0.31 N.m. The negative sign indicates that it will be clockwise.

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Chapter 10, Problem 4E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The answer to “Three forces are applied to a wheel of radius 0.350 m, as shown in ?Fig. E10.4?. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center?” is broken down into a number of easy to follow steps, and 64 words. The full step-by-step solution to problem: 4E from chapter: 10 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: wheel, perpendicular, radius, forces, Net. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 4E from 10 chapter was answered, more than 2402 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13.

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Three forces are applied to a wheel of radius 0.350 m, as