Three forces are applied to a wheel of radius 0.350 m, as shown in ?Fig. E10.4?. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center?

Solution 4E We have to calculate the net torque on the wheel due to the given forces. Mathematically, Torque = Force X Perpendicular distance between the force and the axis. Let us have a look at the following figure. Force 11.9 N The perpendicular distance of this force from the axis is zero. Therefore, this force can not produce a torque. So, torque produced by 11.9 N force is zero. = 0 1 Force 8.50 N The perpendicular distance of this force from the axis of rotation is 0.350 m. Moreover, this force acts counterclockwise. Hence the torque produced by it will be positive. Torque by the force 8.50 N, 2 = 8.50 N × 0.350 m = 2.97 N.m Force 14.6 N This force has two components...