The solid wood door of a gymnasium is 1.00 m wide and 2.00 | StudySoup

Textbook Solutions for University Physics

Chapter 10 Problem 92P

Question

The solid wood door of a gymnasium is 1.00 m wide and 2.00 m high, has total mass 35.0 kg, and is hinged along one side. The door is open and at rest when a stray basketball hits the center of the door head-on, applying an average force of 1500 N to the door for 8.00 ms. Find the angular speed of the door after the impact. [Hint: Integrating Eq. (10.29) yields \Delta \(L_{z}=\int_{t_{1}}^{t_{2}}\left(\sum \tau_{z}\right) d t=\left(\sum \tau_{z}\right)_{\mathrm{av}} \Delta t\). The quantity \(\int_{t_{1}}^{t_{2}}\left(\sum \tau_{z}\right) d t\) is called the angular impulse.]

Solution

Solution 92P Step 1 of 5: Given solid wood door has width 1m and height 2m and mass M=35 kg is hit by basketball at the center of the door with a force of 1500 N to the door for 8 ms as shown in the figure below. We need to calculate the angular speed of door after impact.

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

The solid wood door of a gymnasium is 1.00 m wide and 2.00

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