The solid wood door of a gymnasium is 1.00 m wide and 2.00 m high, has total mass 35.0 kg, and is hinged along one side. The door is open and at rest when a stray basketball hits the center of the door head-on, applying an average force of 1500 N to the door for 8.00 ms. Find the angular speed of the door after the impact. [?Hint: ?Integrating Eq. (10.29) yields is called the angular impulse.]

Solution 92P Step 1 of 5: Given solid wood door has width 1m and height 2m and mass M=35 kg is hit by basketball at the center of the door with a force of 1500 N to the door for 8 ms as shown in the figure below. We need to calculate the angular speed of door after impact.