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Solved: Sulfur (S) and fluorine (F) form several different
Chapter 2, Problem 61P(choose chapter or problem)
Sulfur \((S)\) and fluorine \((F)\) form several different compounds. One of them, \(\mathrm{SF}_{6}\), contains 3.55 g of \(F\) for every gram of \(S\). Use the law of multiple proportions to determine \(n\), which represents the number of \(F\) atoms in \(\mathrm{SF}_{n}\), given that it contains 2.37 g of \(F\) for every gram of \(S\).
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QUESTION:
Sulfur \((S)\) and fluorine \((F)\) form several different compounds. One of them, \(\mathrm{SF}_{6}\), contains 3.55 g of \(F\) for every gram of \(S\). Use the law of multiple proportions to determine \(n\), which represents the number of \(F\) atoms in \(\mathrm{SF}_{n}\), given that it contains 2.37 g of \(F\) for every gram of \(S\).
ANSWER:Step 1 of 3
Here we will have to find out the ratio of the masses of fluorine in \(S F\) and \(S F_{6}\).