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Write equations for the following acidbase reactions. Use the information in Table 2-2

Chapter 2, Problem PROBLEM 2-10

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QUESTION:

Write equations for the following acidbase reactions. Use the information in Table 2-2 or Appendix 4 to predict whether the equilibrium will favor the reactants or the products. (a) HCOOH + -CN (b) CH3COO- + CH3OH (c) (CH3)2CHOH + NaNH2 (d) NaOCH3 + HCN (e) HCl + CH3CH2OH (f) H3O+ + CH3O(g) N H + OH (h) N H + COOH (i) SH CH + 3CH2O (j) CH3CH2OH + C C Na+

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QUESTION:

Write equations for the following acidbase reactions. Use the information in Table 2-2 or Appendix 4 to predict whether the equilibrium will favor the reactants or the products. (a) HCOOH + -CN (b) CH3COO- + CH3OH (c) (CH3)2CHOH + NaNH2 (d) NaOCH3 + HCN (e) HCl + CH3CH2OH (f) H3O+ + CH3O(g) N H + OH (h) N H + COOH (i) SH CH + 3CH2O (j) CH3CH2OH + C C Na+

ANSWER:

Problem 2-10

Write equations for the following acid-base reactions. Use the information in Table 2-2 or Appendix 4 to predict whether the equilibrium will favor the reactants or the products.

                                                             Step by step solution

Step 1 of 6

a)

The acid - base reaction between the  formic acid  and cyanide ion  are as follows.

                                 

Here, Cyanide ion acts as a base by accepting a proton from  formic acid to form conjugate acid .

 

The  value of formic acid  - 3.76

The  value of hydrogen cyanide - 9.22.

Formic acid is a stronger acid than the  hydrogen cyanide because formic acid have low

 value. So, the equilibrium always favors from strong acid to weak acid.

Therefore, the equilibrium towards  the product side.

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