The CN triple bond in acetonitrile has a dipole moment of about 3.6 D and a bond length | StudySoup

Textbook Solutions for Organic Chemistry

Chapter 2 Problem 2-28

Question

The \(\mathrm{C} \equiv \mathrm{N}\) triple bond in acetonitrile has a dipole moment of about 3.6 D and a bond length of about 1.16 . Calculate the amount of charge separation in this bond. How important is the charge-separated resonance form in the structure of acetonitrile? acetonitrile

Solution

Step 1 of 4

An individual bond’s polarity is measured as its bond dipole moment which is indicated by the symbol \(\mu\). The formula for evaluating dipole moment can be given as:

\(\mu=q \times d\)

The symmetrical bonds of the organic compounds comprise a bond dipole moment of zero whereas the strongly polar \(\mathrm{C} \equiv \mathrm{N}\) has a dipole moment of 3.6 D.

The charge separation can be obtained from the dipole moment formula which is given as:

\(q=\frac{\mu}{d}\)

Subscribe to view the
full solution

Title Organic Chemistry 9 
Author Leroy G. Wade, Jan W. Simek
ISBN 9780321971371

The CN triple bond in acetonitrile has a dipole moment of about 3.6 D and a bond length

Chapter 2 textbook questions

×

Login

Organize all study tools for free

Or continue with
×

Register

Sign up for access to all content on our site!

Or continue with

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back