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Two ligands, A and B, both form complexes with a

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 78E Chapter 24

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 78E

Two ligands, A and B, both form complexes with a particular metal ion. When the metal ion complexes with ligand A, the solution is green. When the metal ion complexes with ligand B, the solution is violet. Which of the two ligands results in the largest ?

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Solution 78E:The crystal field splitting energy o, determines the color of the coordination complexdepending on the nature of ligands attached to the central metal ion. According to thespectrochemical series, the high spin or weak field ligands absorb longer wavelengths of lightwhich have lower splitting energy (Low o), whereas complexes with low spin/ strong fieldligands absorb light of greater frequency with have higher splitting energy (high o). Thereforethe color we observe in the complexes are the complementary to the color that is absorbed.A photon equal to the energy difference o is absorbed to promote an electron to the higherenergy level.E = h = o o = hc/, where h and c are constants, and is the wavelength of light absorbed.Therefore, o 1/The spectrochemical series for the strength of the ligands areThe color wheel represents the complementary color to that of the absorbed color.\nThe range of visible color is given below… (1) When the metal ion complexes with ligand A, the solution is greenThe solution is green colored. Since the color we observe in the complexes are thecomplementary to the color that is absorbed.The absorbed color for green solution is= RedTHe visible range of wavelength for red color is 625 nm to 740 nmThe average maximum wavelength absorbed for green color solution is = (625+740)/2682.5nm (2) When the metal ion complexes with ligand B, the solution is Violet\nThe solution is violet colored. Since the color we observe in the complexes are thecomplementary to the color that is absorbed.The absorbed color for violet solution is= YellowTHe visible range of wavelength for yellow color is 565 nm to 590 nmThe average maximum wavelength absorbed for green color solution is = (565+590)/2577.5nmWe know that o 1/For Ligand A, = 682.5 nm and for Ligand B, = 577.5 nmSince,(A ligand) > (B ligand) o(B) > o(A)i.e, the high spin or weak field ligands (A) absorb longer wavelengths of light which havelower splitting energy (Low o).i.e, the low spin or strong field ligands (B) absorb shorter wavelengths of light which havehigher splitting energy (High o).

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Chapter 24, Problem 78E is Solved
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Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

The full step-by-step solution to problem: 78E from chapter: 24 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. The answer to “Two ligands, A and B, both form complexes with a particular metal ion. When the metal ion complexes with ligand A, the solution is green. When the metal ion complexes with ligand B, the solution is violet. Which of the two ligands results in the largest ?” is broken down into a number of easy to follow steps, and 47 words. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. Since the solution to 78E from 24 chapter was answered, more than 333 students have viewed the full step-by-step answer. This full solution covers the following key subjects: metal, complexes, ion, ligand, solution. This expansive textbook survival guide covers 82 chapters, and 9454 solutions.

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