Predict the products and mechanisms of the following reactions. When more than one product or mechanism is possible, explain which are most likely.
1-bromohexane is a primary alkyl halide and in presence of a strong base (sodium ethoxide) it mainly undergoes SN2 and possibly E2.
1- bromohexane + Nain 2
ethanol (and possibly E2)
Since 1-bromohexane is primary halide, so it undergoes mainly 2 and as Nais strong base, so E2 reaction may also be observed.
2-chlorohexane is secondary alkyl halide and in presence of a strong base (sodium ethoxide) it undergoes both SN2 and E2 reaction to give a mixture of products.
2-chlorohexane and E2
Na is strong nucleophile (or base), so it will force second order kinetics, either 2 or E2 and since the halide is 2º, so both can occur.
2-chloro-2-methylbutane is tertiary alkyl halide and in presence of strong base (sodium ethoxide) it undergoes E2 reaction to form more substituted alkene as a major product.
This is a 3º halide, and the base is strong, so here only E2 reaction will take place.
2-chloro-2-methylbutane is heated in ethanol:
2-chloro-2-methylbutane is tertiary alkyl halide and ethanol is a weak base. So, the mixture of and...