Problem 1BSC Notation? In analyzing hits by V-l buzz bombs in World War II, South London was partitioned into 576 regions, each with an area of 0.25 km2. A total of 535 bombs hit the combined area of 576 regions. Assume that we want to find the probability that a randomly selected region had exactly two hits. In applying Formula 5-9, identify the values of ?µ, x,? and ?e.? Also, briefly describe what each of those symbols represents.
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Textbook Solutions for Elementary Statistics
Question
In Exercise?, ?conduct the hypothesis test and provide the test statistic, critical value, and/or P-value, and state the conclusion. Baseball Player Births? In his book ?Outliers,? author Malcolm Gladwell argues that more baseball players have birthdates in the months immediately following July 31, because that was the cutoff date for nonschool baseball leagues. Here is a sample of frequency counts of months of birthdates of American-born major league baseball players starting with January: 387, 329, 366, 344, 336, 313, 313, 503, 421, 434, 398, 371. Using a 0.05 significance level, is there sufficient evidence to warrant rejection of the claim that American-born major league baseball players are born in different months with the same frequency? Do the sample values appear to support Gladwell’s claim?
Solution
Solution 10BSC Step 1 By using = 0.05 significance level to test that there is sufficient evidence to warrant rejection of the claim that American-born major league baseball players are born in different months with the same frequency. Expected frequency = 387 + 312 + . . = 376.25 The results are listed in the following table. observed expected O - E (O - E)² / E 387 376.250 10.750 0.307 329 376.250 -47.250 5.934 366 376.250 -10.250 0.279 344 376.250 -32.250 2.764 336 376.250 -40.250 4.306 313 376.250 -63.250 10.633 313 376.250 -63.250 10.633 503 376.250 126.750 42.699 421 376.250 44.750 5.322 434 376.250 57.750 8.864 398 376.250 21.750 1.257 371 376.250 -5.250 0.073 4515 4515.000 93.072 Expected frequency = 376.25 is same for all categories. The Test Statistic here is 2 2 (i i ) = Ei = 93.072 Where O iObserved frequency Ei= Expected frequency
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