Free-radical chlorination of hexane gives very poor yields of 1-chlorohexane, while cyclohexane can be converted to chlorocyclohexane in good yield. (a) How do you account for this difference? (b) What ratio of reactants (cyclohexane and chlorine) would you use for the synthesis of chlorocyclohexane?
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Textbook Solutions for Organic Chemistry
Question
Using the BDEs in Table 4-2 (p. 143), compute the value of \(\Delta H^{\circ}\) for each step in the iodination of methane.
Compute the overall value of \(\Delta H^{\circ}\) for iodination.
Suggest two reasons why iodine does not react well with methane.
Solution
Solution:
Step 1
The iodination of methane can be carried out by the following ways:-
I2 + CH3 I-CH3 + I .
Mechanism:-
1)Initiation:-
This step involves the generation of active species (free radical)
2) Propagation:-
This process involves the growth of a polymer chain by successive addition of monomers during propagation can be represented as follows:-
The value of ΔH° for each step in the formation of iodination of methane can be calculate as,
For breaking I-I , ΔH° = +151 KJ/mole (+ 36 Kcal/mole)
For breaking H-CH3, ΔH° = +435 KJ/mole (+ 104 Kcal/mole)
For making H-I , ΔH° = -297 KJ/Mole (-71 KCal/mole)
Total ΔH° = +138 KJ/mole (+ 33Kcal/mole)
To break I-I ΔH° = +151 KJ/mole (+36 Kcal/mole)
To make I-CH3 ΔH° = -234 KJ/mole (-56Kcal/mole)
Total ΔH° = -83 KJ/mole (-20 Kcal/mole)
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