Solution for problem 5CQQ Chapter 11.3
Question refer to the sample data in the | Ch 11.3 - 5CQQ
Elementary Statistics | 12th Edition
Question? ?refer to the sample data in the following table (based on data from the Bureau of Labor Statistics). The table lists frequencies for randomly selected nonfatal occupation injuries arranged according to day of the week. Assume that we want to use a 0.05 significance level to test the claim that such injuries occur with equal frequency on different days of the week. D a y N u m b e r Given that the ?P?-value for the hypothesis test is 0.971, what do you conclude?
Solution 5CQQ Step1: From the above given problem we have Days mon tue wed thu fri Number 23 23 21 21 19 P-value for the hypothesis test is 0.971 with = 0.05 level of significance Step2: Consider the hypothesis, H 0 Probabilities of getting injuries are equal for all five days of the week. H : At least one of the probabilities of getting injury is different from others. 1 Conclusion: We have P-value for the hypothesis test is 0.971 comparing this to level of significance i.e, the p value(p = 0.971) is greater than the level of significance = 0.05.Hence, we accept null hypothesis at 0.05 level of significance that frequency occurrence of occupation injuries is same for given days of the week.