In a certain track and field event, the shotput has a mass of 7.30 kg and is released with a speed of 15.0 m/s at 40.0° above the horizontal over a competitor’s straight left leg. What are the initial horizontal and vertical components of the momentum of this shotput?

Solution 2E Step 1 of 3: Let +x be along the horizontal motion of the shot put v x vcos Let + y be vertically upward v y vsin Each momentum is the product of mass and corresponding velocity component. Step 2 of 3: The horizontal component of the initial momentum is p x mv x = m vcos = 7.3 kg × 15 m/s × cos 40 0 = 83.9 kg.m/s