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Since for a particle the kinetic energy is given by and

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 10DQ Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 10DQ

Since for a particle the kinetic energy is given by and the momentum by it is easy to show that K =? /2m. How, then, is it possible to have an event during which the total momentum of the system is constant but the total kinetic energy changes?

Step-by-Step Solution:

Solution 10DQ Introduction We have to discuss why kinetic energy changes while keeping momentum constant. Step 1 This is possible because the kinetic energy is not linear function of momentum rather it is the quadratic function. We can divide in two or more parts keeping the momentum same, that is suppose P is the initial momentum then we can divide it in n parts in such a way that P = P +1P + 2... + P n But so the total momentum will remain same. But in general the sum of the squares of the components will not be equal to the sum of the initial momentum , that is 2 2 2 2 P = / P 1 + P 2 + .... +nP So the kinetic energy can be different even if the total momentum remains same because the kinetic energy is a not a linear function of momentum.

Step 2 of 1

Chapter 8, Problem 10DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Since for a particle the kinetic energy is given by and