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Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 97p
Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 97p

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# Jack and Jill are standing on a crate at rest on the ISBN: 9780321675460 31

## Solution for problem 97P Chapter 8

University Physics | 13th Edition

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Problem 97P

Jack and Jill are standing on a crate at rest on the frictionless; horizontal surface of a frozen pond. Jack has mass 75.0 kg. Jill has mass 45.0 kg, and the crate has mass 15.0 kg. They remember that they must fetch a pail of water, so each jumps horizontally from the top of the crate. Just after each jumps, that person is moving away from the crate with a speed of 4.00 m/s relative to the crate. (a) What is the final speed of the crate if both Jack and Jill jump simultaneously and in the same direction? (?Hint?: Use an inertial coordinate system attached to the ground.) (b) What is the final speed of the crate if Jack jumps first and then a few seconds later Jill jumps in the same direction? (c) What is the final speed of the crate if Jill jumps first and then Jack, again in the same direction?

Step-by-Step Solution:
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Solution 97P Throughout this question, we shall have to consider the momentum conservation principle to answer the questions asked. According to this principle, for a system initial momentum = final momentum. Mass of Jack = 75.0 kg Mass of Jill = 45.0 kg Mass of crate = 15.0 kg (a) When Jack and Jill jump simultaneously, (75.0 + 45.0) kg × 4.0 m/s = (75.0 + 45.0 + 15.0) kg × Speed of crate Speed of crate = 480 kg.m/= 3.56 m/s 135 kg Therefore, the speed of the crate is 3.56 m/s. (b) Jack jumps first, So, 75.0 kg × 4.00 m/s = (75.0 + 45.0 + 15.0) kg × Speed of crate Speed of crate = 3135.0 kgs Speed of crate = 2.22 m/s Jill stays back, So, 45.0 kg × 4.00 m/s = (45.0 + 15.0) kg × Speed of crate Speed of crate = 3.00 m/s Therefore. total speed of the crate = 2.22 m/s + 3.00 m/s = 5.22 m/s (c) Jill jumps first, 45.0 kg × 4.00 m/s = (75.0 + 45.0 + 15.0) kg × Speed of crate Speed of crate = 1.33 m/s Jack stays back, 75.0 kg × 4.00 m/s = (75.0 + 15.0) kg × Speed of crate Speed of crate = 3.33 m/s Therefore, total speed of the crate = 1.33 m/s + 3.33 m/s = 4.66 m/s

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##### ISBN: 9780321675460

The answer to “Jack and Jill are standing on a crate at rest on the frictionless; horizontal surface of a frozen pond. Jack has mass 75.0 kg. Jill has mass 45.0 kg, and the crate has mass 15.0 kg. They remember that they must fetch a pail of water, so each jumps horizontally from the top of the crate. Just after each jumps, that person is moving away from the crate with a speed of 4.00 m/s relative to the crate. (a) What is the final speed of the crate if both Jack and Jill jump simultaneously and in the same direction? (?Hint?: Use an inertial coordinate system attached to the ground.) (b) What is the final speed of the crate if Jack jumps first and then a few seconds later Jill jumps in the same direction? (c) What is the final speed of the crate if Jill jumps first and then Jack, again in the same direction?” is broken down into a number of easy to follow steps, and 155 words. Since the solution to 97P from 8 chapter was answered, more than 772 students have viewed the full step-by-step answer. This full solution covers the following key subjects: crate, jumps, jill, Jack, speed. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. This textbook survival guide was created for the textbook: University Physics, edition: 13. The full step-by-step solution to problem: 97P from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. University Physics was written by and is associated to the ISBN: 9780321675460.

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