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The nucleus of 214Po decays radioactively by emitting an

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 75P Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 75P

The nucleus of 214Po decays radioactively by emitting an alpha particle (mass 6.65 × 10?27 kg) with kinetic energy 1.23 × 10?12 J, as measured in the laboratory reference frame. Assuming that the Po was initially at rest in this frame, find the recoil velocity of the nucleus that remains after the decay.

Step-by-Step Solution:

Solution 75P Step 1: Mass of Alpha particle m = 6He x10 -27Kg Mass of Po m = Po x 1.67 x10 -27Kg = 357.38 x10 -27Kg Where 1.67 x10 -27Kg is mass per nucleon. -12 Kinetic Energy of Alpha particle K = 1.Hex 10 J Step 2: Kinetic energy of alpha particles is given by K = 1 m v 2 He 2 He He Where v iHehe speed of alpha particles Step 3: Rearranging the above equation 2K He vHe m He 2*1.2* 1012 vHe 6.6* 1027 v = 1.92 x 10 m/s He 7 Speed of Alpha particles is 1.92 x 10 m/s Step 4: To find the recoil velocity. When an alpha particle is ejected from a Po nucleus, Po experiences an opposite force. Initially the Po nucleus is at rest, hence initial momentum is zero. After emission alpha particle moves in a particular direction and Po nucleus moves in the opposite direction.

Step 5 of 7

Chapter 8, Problem 75P is Solved
Step 6 of 7

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 75P from 8 chapter was answered, more than 449 students have viewed the full step-by-step answer. The answer to “The nucleus of 214Po decays radioactively by emitting an alpha particle (mass 6.65 × 10?27 kg) with kinetic energy 1.23 × 10?12 J, as measured in the laboratory reference frame. Assuming that the Po was initially at rest in this frame, find the recoil velocity of the nucleus that remains after the decay.” is broken down into a number of easy to follow steps, and 53 words. The full step-by-step solution to problem: 75P from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: frame, nucleus, Laboratory, decays, emitting. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460.

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