Force of a Baseball Swing. A baseball has mass 0.145 kg.

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

Problem 8E Chapter 8

University Physics | 13th Edition

  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

4 5 0 233 Reviews
31
2
Problem 8E

Force of a Baseball Swing.? A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball’s velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat.

Step-by-Step Solution:

Solution 8E Step 1: a) initial momentum of the ball, P initialu Where, m - mass of the ball and u - initial velocity Provided, mass of the ball, m = 0.145 kg Initial speed of the ball, u = 45 m/s Therefore, P = 0.145 kg × 45 m/s = 6.525 kg m/s initial Final momentum of the ball, P = mv final Where, m - mass of the ball and v - final velocity Provided, mass of the ball, m = 0.145 kg Final speed of the ball, u = 55 m/s Therefore, P final0.145 kg × 55 m/s = 7.975 kg m/s We should not take signs here because, we are dealing only with magnitudes. Change in momentum of the ball, P = P finalPinitial P = 7.975 kg m/s - 6.525 kg m/s = 1.45 kg m/s Step 2: a) Impulse is the large force acting for a short time. So, Impulse = Force × t We know that, force, F = ma = m (v-u)/t Or, F = ( mv- mu) / t That is, F = (P finalPinitialt Or, F = P / t So, we can write, Impulse = (P / t) × t = P Therefore, the impulse = 1.45 kg m/s

Step 3 of 3

Chapter 8, Problem 8E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 8E from 8 chapter was answered, more than 257 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “Force of a Baseball Swing.? A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball’s velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat.” is broken down into a number of easy to follow steps, and 82 words. The full step-by-step solution to problem: 8E from chapter: 8 was answered by Patricia, our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: ball, magnitude, bat, Baseball, applied. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by Patricia and is associated to the ISBN: 9780321675460.

×
Log in to StudySoup
Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 8e

Forgot password? Reset password here

Join StudySoup for FREE
Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 8e
Join with Email
Already have an account? Login here
Reset your password

I don't want to reset my password

Need help? Contact support

Need an Account? Is not associated with an account
Sign up
We're here to help

Having trouble accessing your account? Let us help you, contact support at +1(510) 944-1054 or support@studysoup.com

Got it, thanks!
Password Reset Request Sent An email has been sent to the email address associated to your account. Follow the link in the email to reset your password. If you're having trouble finding our email please check your spam folder
Got it, thanks!
Already have an Account? Is already in use
Log in
Incorrect Password The password used to log in with this account is incorrect
Try Again

Forgot password? Reset it here