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Force of a Baseball Swing. A baseball has mass 0.145 kg.

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 8E Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 8E

Force of a Baseball Swing.? A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball’s velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat.

Step-by-Step Solution:

Solution 8E Step 1: a) initial momentum of the ball, P initialu Where, m - mass of the ball and u - initial velocity Provided, mass of the ball, m = 0.145 kg Initial speed of the ball, u = 45 m/s Therefore, P = 0.145 kg × 45 m/s = 6.525 kg m/s initial Final momentum of the ball, P = mv final Where, m - mass of the ball and v - final velocity Provided, mass of the ball, m = 0.145 kg Final speed of the ball, u = 55 m/s Therefore, P final0.145 kg × 55 m/s = 7.975 kg m/s We should not take signs here because, we are dealing only with magnitudes. Change in momentum of the ball, P = P finalPinitial P = 7.975 kg m/s - 6.525 kg m/s = 1.45 kg m/s Step 2: a) Impulse is the large force acting for a short time. So, Impulse = Force × t We know that, force, F = ma = m (v-u)/t Or, F = ( mv- mu) / t That is, F = (P finalPinitialt Or, F = P / t So, we can write, Impulse = (P / t) × t = P Therefore, the impulse = 1.45 kg m/s

Step 3 of 3

Chapter 8, Problem 8E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

Since the solution to 8E from 8 chapter was answered, more than 302 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “Force of a Baseball Swing.? A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball’s velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat.” is broken down into a number of easy to follow steps, and 82 words. The full step-by-step solution to problem: 8E from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This full solution covers the following key subjects: ball, magnitude, bat, Baseball, applied. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460.

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