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Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 4e
Get Full Access to University Physics - 13 Edition - Chapter 8 - Problem 4e

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# Two vehicles are approaching an intersection. One is a

ISBN: 9780321675460 31

## Solution for problem 4E Chapter 8

University Physics | 13th Edition

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Problem 4E

Two vehicles are approaching an intersection. One is a 2500-kg pickup traveling at 14.0 m/s from east to west (the -x-direction), and the other is a 1500-kg sedan going from south to north (the +y-direction) at 23.0 m/s. (a) Find the x- and y-components of the net momentum of this system. (b) What are the magnitude and direction of the net momentum?

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Solution 4E a) The velocity of the 2500 kg vehicle is 14 m/s. The velocity of the 1500 kg sedan is 23 m/s. But velocity is a vector quantity and there is a direction associated with it. So, let the diagram be as a xy coordinate system. So, The velocity of the 2500 kg vehicle is -14 m/s. The velocity of the 1500 kg sedan is +23 m/s. These are the only components and the other two components are zero. The x component of momentum of the 2500 kg vehicle is, P 1x= 2500kg × ( 14 m/s) = 35000 kg m/s The y component is, P 1y = 0 The x component of the 1500 kg vehicle is, P2x = 0 The y component of the vehicle is, P 2y= 1500kg × 23 m/s = 34500 kg m/s. Net momentum x and y components are, P = 35000 & P = 34500. x y b) he net momentum is, 2 2 0 P = P x + P y + 2P x cys 90 2 2 = 5000 + 34500 + 2 × 35000 × 34500 × 1 = 69500 kg m/s. The direction is towards the north-west direction.

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