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Two identical 1.50-kg masses are pressed against opposite

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 23E Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 23E

Two identical 1.50-kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the spring by 20.0 cm from its normal length. Find the speed of each mass when it has moved free of the spring on a frictionless horizontal table.

Step-by-Step Solution:

Solution 23E Step 1: Provided, the masses of the bodies as, m = 1.50 kg Force constant of the spring, k = 1.75 N/ cm 1 m = 10 m-2 Therefore, k = 1.75 N/ 10 m = 175 N/ m The compression of the spring, x = 20 cm = 0.2 m 2 The potential energy of the spring during compression, PE = ½ kx PE = ½ × 175 N/m × 0.2 m = 3.5 J 2

Step 2 of 2

Chapter 8, Problem 23E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Two identical 1.50-kg masses are pressed against opposite

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