Solution Found!
Two identical 1.50-kg masses are pressed against opposite
Chapter 10, Problem 23E(choose chapter or problem)
Two identical 1.50-kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the spring by 20.0 cm from its normal length. Find the speed of each mass when it has moved free of the spring on a frictionless horizontal table.
Questions & Answers
QUESTION:
Two identical 1.50-kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the spring by 20.0 cm from its normal length. Find the speed of each mass when it has moved free of the spring on a frictionless horizontal table.
ANSWER:Solution 23E Step 1: Provided, the masses of the bodies as, m = 1.50 kg Force constant of the spring, k = 1.75 N/ cm 1 m = 10 m-2 Therefore, k = 1.75 N/ 10 m = 175 N/ m The compression of the spring, x = 20 cm = 0.2 m 2 The potential energy of the spring during compression, PE = ½ kx PE = ½ × 175 N/m × 0.2 m = 3.5 J 2