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Get Full Access to Chemistry: A Molecular Approach - 3 Edition - Chapter 1 - Problem 45e
Get Full Access to Chemistry: A Molecular Approach - 3 Edition - Chapter 1 - Problem 45e

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Classify each property as physical or chemical.a. the ISBN: 9780321809247 1

Solution for problem 45E Chapter 1

Chemistry: A Molecular Approach | 3rd Edition

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Problem 45E

Classify each property as physical or chemical.

a. the tendency of ethyl alcohol to burn

b. the shine on silver

c. the odor of paint thinner

d. the flammability of propane gas

Step-by-Step Solution:
Step 1 of 3

Solution 45E: Unit conversion (a) millimeter(mm) to nanometer(nm) We know (i) Convert mm to m -3 1.0 mm = 10 m (ii) nm to m 1 nm = 10 m-9 Thus Given unit x Desired un= desired unit 1 x 103 mn u1 nm 6 1 mm x 1 mm x 109 m = 10 nm 6 Thus, 1.0 mm = 1 x 10 nm (b) mg to kg, We know 10 mg = 1 g and 1 mg = 10 g -3 10 g = 1 kg Therefore 1 x103 g 1 kg 1.0 mg x 1.0 mg x 1000g = 1x 10 kg Therefore, 1 mg is equal to 1x 10 kg -6 (c) km to ft Convert the unit by using two or more conversion fectors 1 km = 1000 m 1 m = 100 cm 1 inch = 2.54 cm 1 cm = 1inch/2.54 cm 1 ft = 12 inch Thus 1000 m 100 cm 1 in 1 ft 1 5 1.0 kmx 1k m x 1 m x 2.54 cmx 12 inch 30.48x 10 ft =0.0328 x 10 ft = 3.3 x 10 ft Thus, 1 km is equal to 3.3 x 10 ft 3 d) in. to cm3. We know 1 inch = 2.54 cm (1.0 inch) = (2.54 cm) 3 (1.0 inch) = 16.387 cm 3 3 = 16.4 cm 3 3 Thus, in. is equal to 16.4 cm

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ISBN: 9780321809247

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