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Textbook Solutions for Chemistry: A Molecular Approach

Chapter 9 Problem 41E

Question

Problem 41E

Use Lewis symbols to determine the formula for the compound that forms between each pair of elements.

a.        Sr and Se

b.        Ba and Cl

c.        Na and S

d.        Al and O

Solution

Solution Step 1 of 4 Couple a) Strontium (Sr) belongs to II A group, thus it has two electrons in its outer shell Selenium (Se) belongs to VI A group thus it has six electron in its outer shell. Because of Selenium’s high electronegativity respect to Strontium, Selenium can gain electrons from Strontium. In order to reach their stability, Strontium can give two electrons to Selenium, thus leaving the inner shell complete. On the other hand, Selenium can gain two electrons from strontium, completing its outer shell. This is the reason why Sr and O combine together in a 1:1 ratio, thus obtaining the formula SrO. Strontium turns to be a positive, bivalent, ion (because it loses two electrons) Selenium becomes a negative, bivalent ion (because it acquires two electron). Thus the Lewis formula is

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Title Chemistry: A Molecular Approach 3 
Author Nivaldo J. Tro
ISBN 9780321809247

Use Lewis symbols to determine the formula for the

Chapter 9 textbook questions

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