Write Lewis structures for each molecule or ion. Include | StudySoup

Textbook Solutions for Chemistry: A Molecular Approach

Chapter 9 Problem 76E

Question

Write Lewis structures for each molecule or ion. Include resonance structures if necessary and assign formal charges to all atoms. If necessary, expand the octet on the central atom to lower formal charge.

a. SO42-                 b. HSO4-                 c. SO3                         d. BrO2-

Solution

Solution:Step-1(a)Peroxide ion (O ) has longer bond length than the superoxide ion (O ) - 2 2It is known that the length of the bond is determined by the number of bonded electrons (thebond order). The higher the bond order, the stronger the pull between the two atoms and theshorter the bond length.The reason behind difference between the bond length of this two ions is due the differencein bond order . 2-The bond order of peroxide ion (O ) is, 2Bond order in Oxygen molecule (O ) 2- 2=½ [(Number of bonding electrons) – (number of anti-bonding electrons)]= ½ [10 – 8]= 1With the increase in number of electrons in anti-bonding orbital the stability and bond orderof

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Title Chemistry: A Molecular Approach 3 
Author Nivaldo J. Tro
ISBN 9780321809247

Write Lewis structures for each molecule or ion. Include

Chapter 9 textbook questions

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