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What is the electron sea model for bonding in metals?
Chapter 9, Problem 33E(choose chapter or problem)
Problem 33E
What is the electron sea model for bonding in metals?
Questions & Answers
QUESTION:
Problem 33E
What is the electron sea model for bonding in metals?
ANSWER:
Solution:Step-1 (a) BrF i4square planar where as BF is tetrahe4alBr has 7 valence electrons in its ground state electronic configuration whereas B only has three.Explanation:If you look at the positions of Br and B on the periodic table, they have ground state electronconfigurations of the following:For Br,[Ar]4s23d104p5For B,[He]2s22p1Looking at these electron configurations, it can be seen that the valence shell of bromine (n=4)has 7 electrons, 2 from the s subshell, and 5 in the p subshell.Since Br is the central atom, and is bonded to four F atoms (who also have 7 valence electrons),4 of the 7 electrons in the valence shell of Br will be bonded to an F atom. This means that 3electrons will not be in a bond. Since the compound is negatively charged, this means theadditional electron (carrying the negative charge) will be paired with one of the 3 lone electrons.Drawing this structure out, you will see that the four F's will align in a square plane, and l