Solved: Consider the reaction: A sample of pure NH4HS is placed in a sealed 2.0-L | StudySoup

Textbook Solutions for Introductory Chemistry

Chapter 15 Problem 104P

Question

Consider the reaction:

\(\mathrm{NH}_{4} \mathrm{HS}(s) \rightleftharpoons \mathrm{NH}_{3}(g)+\mathrm{H}_{2} \mathrm{~S}(g)\)

A sample of pure \(\mathrm{NH}_{4} \mathrm{HS}\) is placed in a sealed 2.0-L container and heated to 550 K at which the equilibrium constant is \(3.5^{*} 10^{-3}\). Once the reaction reaches equilibrium, what mass of \(\mathrm{NH}_{3}\) is in the container? (Assume that the sample of \(\mathrm{NH}_{4} \mathrm{HS}\) was large enough that equilibrium could be achieved.)

Solution

Solution 104P:

Step 1:

The equilibrium constant is

Keq = = [NH3][H2S]

Thus, we know that, NH4HS(s) is a solid, so that it is not included into the equilibrium constant.

Keq= 3.5 × 10‒3.

[NH3][H2S] =  3.5 × 10‒3.

From equation, 1 mol NH4HS(s) produces 1.0 mol of NH3(g) and (H2S each.

Thus,

[NH3] = [H2S]

Therefore.

Keq =  [NH3][H2S] =  [NH3]2

[NH3]2 = 3.5 × 10‒3.

[NH3] =  = 0.059 M

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full solution

Title Introductory Chemistry 5 
Author Nivaldo J Tro
ISBN 9780321910295

Solved: Consider the reaction: A sample of pure NH4HS is placed in a sealed 2.0-L

Chapter 15 textbook questions

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