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Complete the table.CompoundMassMolesNumber of

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 49P Chapter 6

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 1 380 Reviews
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2
Problem 49P

Complete the table.

Compound

Mass

Moles

Number of Molecules

H2O

112 kg

_______

_______

N2O

6.33 g

_______

_______

SO2

_______

2.44

_______

CH2Cl

2

_______

0.0643

_______

Step-by-Step Solution:

Solution 49P

Complete the table.

Compound

Mass

Moles

Number of Molecules

H2O

112 kg

6217.04

3.743 1027

N2O

6.33 g

6.55

4.18 1024

SO2

156.321

2.44

1.46 1024

CH2Cl2

5.46

0.0643

3.871022

Step 1:

112 kg of H2O = 112000 g

Molar mass of H2O = 18.015 g/mol

Hence moles = 112000 18.015 = 6217.04moles

Number of molecules = number of moles Avogadro’s number

                            = 6217.04 6.022 1023 = 3.743 1027 number of moles.

Step 2:

6.33g of N2O = How many moles?

Molar mass of N2O= 44.013

Moles = 44.013 6.33 = 6.95  moles

Number of molecules = number of moles Avogadro’s number

                            = 6.95 6.022 1023 = 4.18 1024 number of moles.

Step 3 of 4

Chapter 6, Problem 49P is Solved
Step 4 of 4

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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