In a butane lighter, 9.7 g of butane combine with 34.7 g of oxygen to form 29.3 g carbon dioxide and how many grams of water?
Step 1 of 3
In this question it has been given that, in a butane lighter, 9.7 gm of butane combine with 34.7 g of oxygen and 29.3 g of Carbon dioxide has formed along with H2O.
Here we will have to calculate the amount of water released in the given reaction.
As it is known that, according to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Butane (9.7 gm) + Oxygen (O2) (34.7g) -------> CO2(29.3g) + H2O(x)
Let X gm of H2O has been formed.
9.7 +34.7 = 29.3 +X
44.4 = 29.3+ X
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 49P from 3 chapter was answered, more than 856 students have viewed the full step-by-step answer. This full solution covers the following key subjects: butane, form, combine, dioxide, carbon. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “In a butane lighter, 9.7 g of butane combine with 34.7 g of oxygen to form 29.3 g carbon dioxide and how many grams of water?” is broken down into a number of easy to follow steps, and 26 words. The full step-by-step solution to problem: 49P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM.