Solved: In a butane lighter, 9.7 g of butane combine with 34.7 g of oxygen to form 29.3 | StudySoup

Textbook Solutions for Introductory Chemistry

Chapter 3 Problem 49P

Question

In a butane lighter, 9.7 g of butane combine with 34.7 g of oxygen to form 29.3 g carbon dioxide and how many grams of water?

Solution

Solution 49P

In this question it has been given that, in a butane lighter, 9.7 gm of butane combine with 34.7 g of oxygen and 29.3 g of Carbon dioxide has formed along with H2O.

Here we will have to calculate the amount of water released in the given reaction.

As it is known that, according to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Butane (9.7 gm) +  Oxygen (O2) (34.7g) -------> CO2(29.3g) + H2O(x)

Let X gm of H2O has been formed.

9.7 +34.7 = 29.3 +X

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full solution

Title Introductory Chemistry 5 
Author Nivaldo J Tro
ISBN 9780321910295

Solved: In a butane lighter, 9.7 g of butane combine with 34.7 g of oxygen to form 29.3

Chapter 3 textbook questions

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