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Solved: Calculate the mass of NaCl in a 35-mL sample of a 1.3 M NaCl solution

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 71P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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1
Problem 71P

Calculate the mass of NaCl in a 35-mL sample of a 1.3 M NaCl solution.

Step-by-Step Solution:
Step 1 of 3

Solution: here, we are going to calculate the mass of NaCl in the sample solution.

Step1:

Molarity(M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution.

                                                   Moles of solute

                                Molarity = -------------------------------        ------(1)

                                              Volume of solution in litre

Step2:

In the above problem,

Volume of the solution = 35 mL = 35 / 1000 L = 0.035 L                [1000 mL = 1 L]

Molarity of the solution = 1.3 M

Substituting the values in equation (1), we get,

                                

1.3 M = moles of NaCl / 0.035 L

                    Therefore, moles of NaCl = 1.3 M x 0.035 L

= 0.0455 mol

Step3:

1 mol NaCl = molar mass of NaCl

0.0455 mol NaCl = 0.0455 x molar mass of NaCl

                     = 0.0455 x 58.44 g/mol

                     = 2.659 g.

Thus, the mass of NaCl is 2.659 g.

                                                -------------------------------

Step 2 of 3

Chapter 13, Problem 71P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: Calculate the mass of NaCl in a 35-mL sample of a 1.3 M NaCl solution