How much of a 12.0 M \(\mathrm {HNO_3}\) solution should you use to make 850.0 mL of a 0.250 M \(\mathrm {HNO_3}\) solution?

Equation Transcription:

Text Transcription:

HNO_3

Solution 87P:

Here, we are going to calculate the volume of 12.0 M HNO3 solution by using dilution equation.

M1V1= M2V2 ------(1)

Where, M1 and V1 are Molarity and volume of the initial solution whereas M2 and V2 are the Molarity and volume of the solution.

From the Question,

It is given that,

M1 (initial Molarity) =0.250 M

V1 (initial volume) = 850.0 mL

M2 (final Molarity) =12 M

V2 (initial volume) = ?

Thus, from equation (1)

M1V1= M2V2 ------(1)

V2 = M1V1/M2

= = 17.708 mL

The final volume of HNO3 is 17.708 mL

Thus, 17.708 mL of 12 M HNO3 is required to make 850 mL of 0.250M HNO3