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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 97p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 13 - Problem 97p

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# Calculate the molality of each solution.(a) 0.25 mol solute; 0.250 kg solvent(b) 0.882

ISBN: 9780321910295 34

## Solution for problem 97P Chapter 13

Introductory Chemistry | 5th Edition

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Problem 97P

Problem 97P

Calculate the molality of each solution.

(a) 0.25 mol solute; 0.250 kg solvent

(b) 0.882 mol solute; 0.225 kg solvent

(c) 0.012 mol solute; 23.1 g solvent

Step-by-Step Solution:
Step 1 of 3

Molality :

Molality is a property of a solution and is defined as the number of moles of solute per kilogram of solvent.

The SI unit for molality is mol/kg.

A solution with a molality of 3 mol/kg is often described as "3 molal" or "3 m."

(a) 0.25 mol solute; 0.250 kg solvent.

We know that

Molality = no.of moles of solute /Kg of solvent .

=0.25 m/0.250 Kg

= 1 molal.

(b) 0.882 mol solute; 0.225 kg solvent

We know that

Molality = no.of moles of solute /Kg of solvent .

=0.882 m/0.225 kg .

=3.92 m.

(c) 0.012 mol solute; 23.1 g solvent

We know that

Molality = no.of moles of solute /Kg of solvent .

Convert grams into kg 23.1=0.0231 kg

=0.012 m /0.0231 Kg .

=   0.519 m.

Step 2 of 3

Step 3 of 3

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Calculate the molality of each solution.(a) 0.25 mol solute; 0.250 kg solvent(b) 0.882