Solution Found!

These exercises are not divided

Chapter , Problem 91AE

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

These exercises are not divided by category, although they are roughly in the order of the topics in the chapter. They are not paired.

(a) Assuming the dimensions of the nucleus and atom shown in Figure 2.11, what fraction of the volume of the atom is taken up by the nucleus?

A mass spectrometer. Cl atoms are introduced at A and are ionized to form \(\mathrm{Cl}^{+}\) ions, which are then directed through a magnetic field. The paths of the ions of the two Cl isotopes diverge as they pass through the field.

(b) Using the mass of the proton from Table 2.1 and assuming its diameter is \(1.0 \times 10^{-15} \mathrm{~m}\), calculate the density of a proton in \(\mathrm{g/cm}^{3}\).

Table 2.1 Comparison of the Proton, Neutron, and Electron

Particle

Charge

Mass (amu)

Proton

Positive (1+)

1.0073

Neutron

None (neutral)

1.0087

Electron

Negative (1-)

\(5.486 \times 10^{-4}\)

Equation Transcription:

Text Transcription:

Cl^+

^37Cl^+

^35Cl^+

1.0x10^-15 m

g/cm^3

5.48610^-4

Questions & Answers

QUESTION:

These exercises are not divided by category, although they are roughly in the order of the topics in the chapter. They are not paired.

(a) Assuming the dimensions of the nucleus and atom shown in Figure 2.11, what fraction of the volume of the atom is taken up by the nucleus?

A mass spectrometer. Cl atoms are introduced at A and are ionized to form \(\mathrm{Cl}^{+}\) ions, which are then directed through a magnetic field. The paths of the ions of the two Cl isotopes diverge as they pass through the field.

(b) Using the mass of the proton from Table 2.1 and assuming its diameter is \(1.0 \times 10^{-15} \mathrm{~m}\), calculate the density of a proton in \(\mathrm{g/cm}^{3}\).

Table 2.1 Comparison of the Proton, Neutron, and Electron

Particle

Charge

Mass (amu)

Proton

Positive (1+)

1.0073

Neutron

None (neutral)

1.0087

Electron

Negative (1-)

\(5.486 \times 10^{-4}\)

Equation Transcription:

Text Transcription:

Cl^+

^37Cl^+

^35Cl^+

1.0x10^-15 m

g/cm^3

5.48610^-4

ANSWER:

Step 1 of 3

The volume of a sphere can be calculated by the following formula;

                                                                  ...........................(1)

Here,

V = Volume of sphere

r = Radius

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back