Solution Stoichiometry and Chemical Analysis
Chapter , Problem 84E(choose chapter or problem)
Solution Stoichiometry and Chemical Analysis (Section 4.6)
The distinctive odor of vinegar is due to acetic acid, \(\mathrm {CH_3COOH}\), which reacts with sodium hydroxide according to:
\(\mathrm{CH}_{3} \mathrm{COO}(a q)+\mathrm{NaOH}(a q) \longrightarrow{\mathrm{H}_{2} \mathrm{O}(l)}+\mathrm{NaCH}_{3} \mathrm{OO}(a q)\)
If 3.45 mL of vinegar needs 42.5 mL of \(0.115\ M\ \mathrm {NaOH}\) to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.00-qt sample of this vinegar?
Equation Transcription:
Text Transcription:
CH_{3}COOH
CH_{3}COO(aq) + NaOH(aq){rightarrow}H_{2}O(l) + NaCH_{3}OO(aq)
0.115 M NaOH
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