(a) Identify the BrnstedLowry acid and base in the reaction + + = H = N = Cl +
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Textbook Solutions for Chemistry: The Central Science
Question
Succinic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{4}\right)\), which we will denote \(\mathrm{H}_{2} \mathrm{Suc}\), is a biologically relevant diprotic acid with the structure shown below. It is closely related to tartaric acid and malic acid (Figure 16.1). At \(25^{\circ} \mathrm{C}\), the acid-dissociation constants for succinic acid are \(K_{a 1}=6.9 \times 10^{-5} \text { and } K_{a 2}=2.5 \times 10^{-6}\).
(a) Determine the pH of a 0.32 M solution of \(\mathrm{H}_{2} \mathrm{Suc}\) at \(25^{\circ} \mathrm{C}\), assuming that only the first dissociation is relevant.
(b) Determine the molar concentration of \(\text { Suc }^{2-}\) in the solution in part (a).
(c) Is the assumption you made in part (a) justified by the result from part (b)?
(d) Will a solution of the salt NaHSuc be acidic, neutral, or basic?
Solution
Problem 108AESuccinic acid (H2C4H604), which we will denote H Suc, is a biologically relevant diprotic acid 2with the structure shown below. It is closely related to tartaric acid and malic acid (Figure). At 25 -5°C, the acid-dissociation constants for succinic acid are K a1= 6.9 x 10 and K = 2.5 x 10 .-6 a2(a) Determine the pH of a 0.32 M solution of H Suc at 25 °C, assum2g that only the firstdissociation is relevant,(b) Determine the molar concentration of Suc in the solution in part (a),(c) Is the assumption you made in part (a) justified by the result from part (b)(d) Will a solution of the salt NaHSuc be acidic, neutral, or basicFigure Two organic acids: Tartartic acid, H2C4H406, and malic acid, H2C4H405. Step-by-step solution Step 1 of 5 (a) -5 -6Dissociation Constants of Succinic Acid (H Suc) are K 2 a1= 6.9 x 10 and K a2= 2.5 x 10The equilibrium reaction for succinic acid for its first ionization is as follows:\nH2uc(aq) HSuc (aq) + H (aq)+ H2ucc HSuc - H+ Initial Concentration (M) 0.32 0 0 Change in Concentration (M) -x +x +x Equilibrium Concentration (M) (0.32 - x x xThe equilibrium constant expression is as follows: + [H ][HSuc ] Ka1 [H Suc] 2 (x)(x) 6.9 x 10 =5 0.32 x (x ) = 0.32 xSolving for x, assuming 0.32 - x 0.32 (very less acid dissociates in comparison to its initialconcentration). 2 -5x = (6.9 x 10 )(0.32) 2 -5x = 2.2 x 10 x = 2.2 × 10 5 -3 = 4.7 x 10 M + -3The concentration of [H ] is 4.7 x 10 MThe pH of the solution is as follows:pH = -log (4.7 x 10 ) -3 = 2.33Hence, the pH of 0.32 M solution of first dissociation of Succinic acid is 2.33 .
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